Need help w Gear Box Design
Posted: Tue Jan 07, 2014 7:21 pm
If any of you out there are experts on this subject or just highly knowledgeable, perhaps you can guide me thru this. I'm attempting to determine what gear ratio I need to design to move a model vehicle at scale speeds.
The parameters are:
Max motor RPMs are 2000
Powered by a 7.2 v DC battery
The prototype vehicle ran at a max speed of 56 MPH
This is 3.5 MPH if in 1/16th sxale.....=18,480 ft/hr....=308 ft/min...=3,696 inches/min
There are 6 driving wheels on the model…..each with a circumference of 7.59”….meaning the model vehicle covers 7.59” for every one revolution turned.
Thus in 1/16th scale, it would take 486 revolutions/min to travel the 3,696 inches.... to be at a scale 56 MPH speed.
However, all of this is at “no load” on the motor. The model vehicle weighs 2.44 pounds……=39 ounces.
The pinion gear has 8 teeth. Thus the questions are:
How many gears and what teeth per each gear is needed?
At “no load” , using an 8 tooth pinion (#1 gear), a 14 tooth #2 gear, with a second 8 tooth gear attached to it, driving a 19 tooth #3 gear, works out to 481.2 revs/mins…..which is close enough
!! (I used Impact’s Gear Ratio Simulator for this calculation)…. http://jbwid.com/art74j.htm
But how do I factor in the 39 ozs of load that the motor will be pulling?….and what about effectts of friction from the moving parts....(drive shafts, U-joints, gear teeth, axels, etc....maybe these can be ignored on a model)
Certainly this extra load requires more revolutions/min to move everything !!
Is there a formula for this calculation?
And lastly…….does anyone know where to order plastic gears with the required number of teeth……like those used in Tamiya gear boxes?
Thanks for any assist. PP
The parameters are:
Max motor RPMs are 2000
Powered by a 7.2 v DC battery
The prototype vehicle ran at a max speed of 56 MPH
This is 3.5 MPH if in 1/16th sxale.....=18,480 ft/hr....=308 ft/min...=3,696 inches/min
There are 6 driving wheels on the model…..each with a circumference of 7.59”….meaning the model vehicle covers 7.59” for every one revolution turned.
Thus in 1/16th scale, it would take 486 revolutions/min to travel the 3,696 inches.... to be at a scale 56 MPH speed.
However, all of this is at “no load” on the motor. The model vehicle weighs 2.44 pounds……=39 ounces.
The pinion gear has 8 teeth. Thus the questions are:
How many gears and what teeth per each gear is needed?
At “no load” , using an 8 tooth pinion (#1 gear), a 14 tooth #2 gear, with a second 8 tooth gear attached to it, driving a 19 tooth #3 gear, works out to 481.2 revs/mins…..which is close enough

But how do I factor in the 39 ozs of load that the motor will be pulling?….and what about effectts of friction from the moving parts....(drive shafts, U-joints, gear teeth, axels, etc....maybe these can be ignored on a model)
Certainly this extra load requires more revolutions/min to move everything !!
Is there a formula for this calculation?
And lastly…….does anyone know where to order plastic gears with the required number of teeth……like those used in Tamiya gear boxes?
Thanks for any assist. PP