The parameters are:
Max motor RPMs are 2000
Powered by a 7.2 v DC battery
The prototype vehicle ran at a max speed of 56 MPH
This is 3.5 MPH if in 1/16th sxale.....=18,480 ft/hr....=308 ft/min...=3,696 inches/min
There are 6 driving wheels on the model…..each with a circumference of 7.59”….meaning the model vehicle covers 7.59” for every one revolution turned.
Thus in 1/16th scale, it would take 486 revolutions/min to travel the 3,696 inches.... to be at a scale 56 MPH speed.
However, all of this is at “no load” on the motor. The model vehicle weighs 2.44 pounds……=39 ounces.
The pinion gear has 8 teeth. Thus the questions are:
How many gears and what teeth per each gear is needed?
At “no load” , using an 8 tooth pinion (#1 gear), a 14 tooth #2 gear, with a second 8 tooth gear attached to it, driving a 19 tooth #3 gear, works out to 481.2 revs/mins…..which is close enough

But how do I factor in the 39 ozs of load that the motor will be pulling?….and what about effectts of friction from the moving parts....(drive shafts, U-joints, gear teeth, axels, etc....maybe these can be ignored on a model)
Certainly this extra load requires more revolutions/min to move everything !!
Is there a formula for this calculation?
And lastly…….does anyone know where to order plastic gears with the required number of teeth……like those used in Tamiya gear boxes?
Thanks for any assist. PP