Electronics advice needed
Posted: Sun Jul 26, 2015 1:19 pm
I have built a custom IR sensor loom so that I can remote mount a battle system in my Panther. I am using an Elmod board, and Thomas kindly sent me this schematic showing how the Tamiya wiring is linked back to the Elmod 5 pin socket.
5. Status LED(+) VCC
4. Sensor Signal
3. Sensor GND.
2. Sensor Output
1. Status LED (-)
It does not have a seperate 2 pin IR emitter plug, it shares the 5 pin socket. I interpreted the schematic as follows, it is in the reverse order to the schematic just to complicate things, as looking at the board the schematic is reversed:
1. Status LED (-)
2. Sensor Output
3. Sensor GND.
4. Sensor Signal and IR(-)
5. Status LED(+) and IR(+) This is VCC eg constant 5v supply.
The IR emitter is connected to 4(-) & 5(+).
The status led's are connected to 1(-) & 5(+).
This should all have been fairly simple, but I am pulling my hair out.
What happens?
No IR emitter connected = The sensors do not detect shots.
IR emitter connected = Shots detected but IR stays lit on 2.3v. If I fire a shot the voltage increases to 2.9v.
Remove sensor = IR emitter behaves normally. No shot = 0v. Shot = 5v.
If I remove the signal leg of the sensor from the circuit and attach it to the (-) leg of the IR emitter, it completes the circuit and I get permament 2.3v, eg a dimly lit led.
So, there is a permanent 2.3v circuit going through the sensor to the signal leg, that is permanently lighting the emitter (I am using a standard visible 5v led so that I can see the led, rather than an IR led which would be invisible).
Thomas speaks good English, but not perfect, so before I go back to him, is there anyone out there who can tell me whether I have made a schoolboy error. I actually had it all working perfectly while I was constructing a prototype, but I have no idea what I did differently to make it work???
I can't find a Tamiya pinout anywhere, but if 3, 4 & 5 are the sensor, 1 & 2 are the status led's, and the IR is seperate, I really need to know which is which to get my circuit correct.
Any knowledgeble help would be much appreciated.
Cheers
RobG
5. Status LED(+) VCC
4. Sensor Signal
3. Sensor GND.
2. Sensor Output
1. Status LED (-)
It does not have a seperate 2 pin IR emitter plug, it shares the 5 pin socket. I interpreted the schematic as follows, it is in the reverse order to the schematic just to complicate things, as looking at the board the schematic is reversed:
1. Status LED (-)
2. Sensor Output
3. Sensor GND.
4. Sensor Signal and IR(-)
5. Status LED(+) and IR(+) This is VCC eg constant 5v supply.
The IR emitter is connected to 4(-) & 5(+).
The status led's are connected to 1(-) & 5(+).
This should all have been fairly simple, but I am pulling my hair out.
What happens?
No IR emitter connected = The sensors do not detect shots.
IR emitter connected = Shots detected but IR stays lit on 2.3v. If I fire a shot the voltage increases to 2.9v.
Remove sensor = IR emitter behaves normally. No shot = 0v. Shot = 5v.
If I remove the signal leg of the sensor from the circuit and attach it to the (-) leg of the IR emitter, it completes the circuit and I get permament 2.3v, eg a dimly lit led.
So, there is a permanent 2.3v circuit going through the sensor to the signal leg, that is permanently lighting the emitter (I am using a standard visible 5v led so that I can see the led, rather than an IR led which would be invisible).
Thomas speaks good English, but not perfect, so before I go back to him, is there anyone out there who can tell me whether I have made a schoolboy error. I actually had it all working perfectly while I was constructing a prototype, but I have no idea what I did differently to make it work???
I can't find a Tamiya pinout anywhere, but if 3, 4 & 5 are the sensor, 1 & 2 are the status led's, and the IR is seperate, I really need to know which is which to get my circuit correct.
Any knowledgeble help would be much appreciated.
Cheers
RobG