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Q: A wire 2.5m long has a cross-sectional area of 2.5 mm^2. It is hung vertically and a 4.5 kg mass is hungfrom it. Byhow much does the wire stretch if Young's modulus for that material is 2.0 x 10^11 N/m^2 ?

so i did Y = ( F / A ) / ( del L / L )

2.0 x 10 ^ 11 N/m^2 = (( 4.5 kg * 9.81 m / s^2 ) / (0.0025 m^2)) / ( del L / 2.5 )

delta L = ((4.5 kg)(9.81 m/s^2)(2.5m))/((.0025m^2)(2x10^11 N / m^2))

= 2.21 x 10 ^ -7 meters